Question
What is the molarity of the concentrated solution?
Answer
Density = 1.22g/ml (1220g/L); Assay = 90%; MW = 46.03Molarity = (density (g/l) x (assay%/100)) ÷ mol wt
Therefore: (1220 x 0.90) ÷ 46.03 = 23.85M
Formic acid 90% (conc.)
S8001137-1L
Molarity = (density (g/l) x (assay%/100)) ÷ mol wt
Therefore: (1220 x 0.90) ÷ 46.03 = 23.85M