Question
What is the molarity of the concentrated solution?
Answer
Density = 1.84g/ml (1840g/L); Assay = 98%; MW = 98.08.Molarity = (density (g/l) x (assay%/100)) ÷ mol wt
Therefore: (1840 x 0.98) ÷ 98.08 = 18.39M
Sulphuric acid 98% (conc.)
S8001449
Molarity = (density (g/l) x (assay%/100)) ÷ mol wt
Therefore: (1840 x 0.98) ÷ 98.08 = 18.39M